计算最小车辆转弯半径和通道宽度
2025-03-29 20:02:43发布 浏览22次 信息编号:201882
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计算最小车辆转弯半径和通道宽度
计算车辆最小转弯半径和通道宽度
情况1:
普通卡车转弯处
定义c = 2ml = 8md = 2mm = 1.792mb = 2.060mk =2.5mθ= 30°
r1 =√{[(L+D)/tanθ]²+c²}
r2 =√{[(L+d)/tanθ-(km)/2]+l²}+bm/2
R3 =(L+D)/SINθ=(8+2)/SIN30°
R1R2小于R3,因此R3用作计算标准(无路边屏障可以计算为R2)
R3 =(L+D)/SINθ=(8+2)/SIN30°= 20m
s =(L+D)/tanθ=(8+2)/tan30°= 17.32m
R = SK = 17.32-2.5 = 14.82m
宽度= R3-R = 20-14.82 = 5.18m
转弯角:t =/{s- [k-(km)/2]} = 27.8°
情况2:
拖车的所有者很短,副司机是领导者,而转折状态
定义c = 2ml = 8md = 2mp = q = 0.5mu = 4me = 1MK = 2.5mm = 1.792mb =2.060mθ= 30°
r1 =√{[(L+D)/tanθ]²+c²}
r2 =√{[(L+d)/tanθ-(km)/2]+l²}+bm/2
R3 =(L+D)/SINθ=(8+2)/SIN30°
r4 =√{√{√{{(l+d)/tanθ-k/2]²+(l+d+p)²-(q+u)²}+k/2}}+e²}
R1R2小于R3,可以控制R4,因此R3用作计算标准(在不同情况下转弯半径不同)
R3 =(L+D)/SINθ=(8+2)/SIN30°= 20m
s =(L+D)/tanθ=(8+2)/tan30°= 17.32m
R = SK = 17.32-2.5 = 14.82m
宽度= R3-R = 20-14.82 = 5.18m
(L+D+P)/(R+K/2)=(8+2+0.5)/(14.82+1.25)= 32.022°
(U+Q)/(R+K/2)=(4+0.5)/(14.82+1.25)= 13.977°
转弯角:©=(32.022°+13.977°)= 45.999°
验证在转弯不转弯时,验证汽车前部需要拉直所需的宽度:
t =√[s²+(l+d+p+q+u+e)]²=√[17.32²+(6+1+5)]²=√444= 21.07m
宽度= TR = 21.07-14.82 = 6.2513m
情况3
车主的汽车很长,子车很短,转弯状态
定义:c = 2ml = 8md = 2mp = q = 0.5mu = 4me = 1MK = 2.5mm = 1.792mb =2.060mθ= 30°
r1 = l/sinθ+(bm)/2 = 16.134m
r2 =√{(L+c)²+[l/tanθ+(km)/2]²} = 17.376m(请注意,θ与3和2不同)
蓝色三角形的长右边缘是:l/tgθ-m/2 = 17.32-1.792/2 = 12.96m
蓝色三角行的斜边是:√[12.96²+(2+ 0.5)²] = 13.2m
绿色三角形的长右边缘是:√[13.2²-(0.5+4)²] = 124m
R = R2-R = 12.4-2.5/2 = 11.16m
道路宽度= 17.376-11.16 = 6.22m
汽车的转弯角为:.96/13.2+.5/13.2 = 11°+20°= 31°
验证在转弯不转弯时,验证汽车前部需要拉直所需的宽度:
t =√[(11.16+2.5)²+(12+1+2.5)²] = 20.66m
道路宽度= 20.66-11.16 = 9.5m
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